Question

Write the first three terms of the sequence.
An = 4n-1/n^2+4

Answer 1

Answer: 3/5, 7/8, and 11/13.

Using the given formula for the sequence An = (4n-1)/(n^2+4), let's find the first three terms.

Term 1 (n=1): A1 = (4(1)-1)/((1)^2+4) = (3)/(1+4) = 3/5

Term 2 (n=2): A2 = (4(2)-1)/((2)^2+4) = (7)/(4+4) = 7/8

Term 3 (n=3): A3 = (4(3)-1)/((3)^2+4) = (11)/(9+4) = 11/13

So, the first three terms of the sequence are 3/5, 7/8, and 11/13.