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2x (3x+1) (4-2x) = 0​

2x (3x+1) (4-2x) = 0​
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5 votes
2x (3x+1) (4-2x) = 0​

User See
by
7.8k points

1 Answer

1 vote

Answer:

x=0. (AKA: NO SOLUTION)

Explanation:

2x (3x+1) (4-2x) = 0​

6x+2x (4-2x)=0

8x (4-2x)=0

32x-16x=0

16x=0

*divide each side by 16*

x=0

User Seasong
by
8.1k points
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