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When f = 2 and g = 8, n = 4. If n varies jointly with f and g, what is the constant of variation?

User Sirion
by
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2 Answers

3 votes


\blue{\huge {\mathrm{CONSTANT \; VARIATION}}}


\\


{===========================================}


{\underline{\huge \mathbb{Q} {\large \mathrm {UESTION : }}}}

  • When f = 2 and g = 8, n = 4. If n varies jointly with f and g, what is the constant of variation?


{===========================================}


{\underline{\huge \mathbb{A} {\large \mathrm {NSWER : }}}}

  • The constant of variation is 1/4.


{===========================================}


{\underline{\huge \mathbb{S} {\large \mathrm {OLUTION : }}}}

If n varies jointly with f and g, the relationship between them can be written as:


  • \sf n = k * f * g

where:

  • k is the constant of variation.

Using the given information, we can solve for k as follows:


  • \begin{aligned}\sf n&=\sf k* f* g \\\sf 4& =\sf k* 2* 8 \\\sf 4& =\sf 16k \\\sf k& =\sf (4)/(16) \\\sf k& =\sf (1)/(4)\end{aligned}

Therefore, the constant of variation is 1/4.


{===========================================}

User Henryk Budzinski
by
7.7k points
0 votes

Answer:

The constant of variation is ¹/₄.

Explanation:

When n varies jointly with f and g, we can write the following equation:


\boxed{n \propto fg \implies n = kfg}

where k is the constant of variation.

We are given that f = 2, g = 8, and n = 4.

Substitute these values into the equation:


\implies 4 = k \cdot 2 \cdot 8

Solve for k:


\implies 4 = 16k


\implies (4)/(16) = (16k)/(16)


\implies (1)/(4)=k

Therefore, the constant of variation is ¹/₄.

User TheRealFakeNews
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