Question

1. Supposing that the egg was dropped from the top of the stairs without the apparatus, calculate

what the velocity of the egg would be as it landed. What is its momentum? The height of the drop is
4.5m, and the mass of the egg is 50 g. I

Answer 1

Step-by-step explanation:

The amount of POTENTIAL energy (mgh) is converted entirely to KINETIC energy ( 1/2 mv^2) at instant before impact

mgh = 1/2 mv^2

gh = 1/2 v^2

2 gh = v^2

v = sqrt ( 2 g h) = sqrt ( 2 * 9.81 * 4.5) = 9.4 m/s

Momentum = m * v = .05 kg * 9.4 m/s = .47 kg m/s