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How many molecules are in 4.5 moles of Iron (ii) nitrite???

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There are approximately 2.71 * 10^24 molecules in 4.5 moles of iron (ii) nitrite

We need to use Avogadro's number, which is approximately 6.022 * 10^23 molecules per mole.

The molecular formula of iron (ii) nitrite is Fe(NO2)2.

The formula to be used is: number of molecules = number of moles * Avogadro's number

Number of molecules = 4.5 moles * 6.022 * 10^23 molecules/mole

Number of Molecules = 2.71 * 10^24 molecules

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