Question

The function f(x) is shown on the graph. 50 POINTS

The graph shows a downward opening parabola with a vertex at 2 comma 16, a point at negative 2 comma 0, a point at 6 comma 0, a point at 0 comma 12, and a point at 4 comma 12.

What is the standard form of the equation of f(x)?
f(x) = x2 + 4x + 12
f(x) = x2 − 4x − 12
f(x) = −x2 + 4x + 12
f(x) = −x2 − 4x − 12

Answer 1

f(x) = −x2 + 4x + 12

Explanation:

Answer 2

(c) f(x) = -x² +4x +12

Explanation:

You want the equation of the downward-opening parabola with vertex (2, 16) through point (0, 12).

Downward-opening

The fact that the parabola opens downward tells you that the leading coefficient is negative. This eliminates choices A and B.

Y-Intercept

The point (0, 12) tells you the constant in the standard form equation is +12. This eliminates choices B and D.

The only viable answer choice is C, f(x) = -x² +4x +12.

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