Answer:
We can use the impedance triangle to solve this problem. In a series RC circuit, the impedance triangle is formed by the resistance (R), the capacitive reactance (Xc), and the impedance (Z), where:
Z² = R² + Xc²
We know that the resistance (R) is 14 ohms and the impedance (Z) is 25 ohms. We can rearrange the impedance triangle formula to solve for the capacitive reactance (Xc):
Xc = √(Z² - R²)
Plugging in the values we know, we get:
Xc = √(25² - 14²) = √(625 - 196) = √429
Therefore, the capacitive reactance of the circuit is approximately 20.74 ohms (rounded to two decimal places).