Answer:
We can solve this problem using the kinematic equation:
v² = u² + 2as
where v is the final velocity, u is the initial velocity, a is the acceleration, s is the distance travelled.
Here, the initial velocity is u = 50 m/s, the final velocity is v = 20 m/s, the acceleration is a = -10 m/s² (negative because the car is decelerating), and we want to find the distance travelled, which is s.
Plugging in these values into the equation, we have:
20² = 50² + 2(-10)s
400 = 2500 - 20s
20s = 2100
s = 105
Therefore, the distance travelled by the car is 105 meters. The answer is option B.