Question

Can you help me with this guys

Answer 1

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Step-by-step explanation:...

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Answer 2

see explanation

Explanation:

given a quadratic function in standard form

f(x) = ax² + bx + c ( a ≠ 0 ) , then

the x- coordinate of the vertex is

`x_(vertex)` = -
`(b)/(2a)`

(a)

f(x) = 2x² +16x + 35 ← is in standard form

with a = 2 , b = 16 , then

`x_(vertex)` = -
`(16)/(2(2))` = -
`(16)/(4)` = - 4

substitute x = - 4 into f(x) for corresponding y- coordinate

f(- 4) = 2(- 4)² + 16(- 4) + 35 = 2(16) - 64 + 35 = 32 - 29 = 3

vertex of function 1 is (- 4, 3 )

(b)

from the graph the vertex ( turning point ) is (- 2, 4 )

vertex of function 2 is (- 2, 4 )

(c)

the minimum value of the functions is the value of the y- coordinate of the vertex.

minimum value of function 1 is 3

minimum value of function 2 is 4

then function 1 has the smaller minimum value