Answer:
see explanation
Explanation:
given a quadratic function in standard form
f(x) = ax² + bx + c ( a ≠ 0 ) , then
the x- coordinate of the vertex is
= -
(a)
f(x) = 2x² +16x + 35 ← is in standard form
with a = 2 , b = 16 , then
= -
= -
= - 4
substitute x = - 4 into f(x) for corresponding y- coordinate
f(- 4) = 2(- 4)² + 16(- 4) + 35 = 2(16) - 64 + 35 = 32 - 29 = 3
vertex of function 1 is (- 4, 3 )
(b)
from the graph the vertex ( turning point ) is (- 2, 4 )
vertex of function 2 is (- 2, 4 )
(c)
the minimum value of the functions is the value of the y- coordinate of the vertex.
minimum value of function 1 is 3
minimum value of function 2 is 4
then function 1 has the smaller minimum value