Question

1.2 Given: x² + 2bx + 3c=0 Solve for x in terms of b by completing the square.​

Answer 1

`\sf x^2 + 2bx + 3c &= 0 \\`

`\sf\longrightarrow \: x^2 + 2bx &= -3c \\`

`\sf\longrightarrow \: x^2 + 2bx + b^2 &= b^2 - 3c \\`

`\sf\longrightarrow \: (x + b)^2 &= b^2 - 3c \\`

`\sf\longrightarrow \: x + b &= \pm √(b^2 - 3c) \\`

`\diamond\sf\longrightarrow \: x &= -b \pm √(b^2 - 3c)\\`

`\huge{\bigstar{\underline{\boxed{\sf{\color{red}{Sumit\:Roy}}}}}}\\`