Answer:
equation of the line is
10x-y=19
Explanation:
Given:
(2,1) parallel to 10x-y=2
we have to find the slope
10x-y=
=>y=1x-2
Therefore slope of the line is
m=10
Now, equation of the slope m passing through a point (x1, y1)
is y-y1=m(x-x1)
Here the point is (2,1) and slope m=10.
=>equation of the line is:
y-1=10(x-2)
y-1=10x-20
20-1=10x-y
19=10x-
=>10x-y=19
Hence the equation of the line
is 10x-y=19.