Question

An aeroplane leaves London 11:30 p.m. and reaches Ghana 4,415 km away at 5:30 a.m. the next morning. Find correct to the nearest whole number, the average speed of the aeroplane in km/h.​

Answer 1

`\begin{align}\text{Time elapsed} &= 5:30\text{ a.m.} - 11:30\text{ p.m.} \ &= 6\text{ hours}\end{align}`

`\begin{align}\text{Average speed} &= \frac{\text{Distance traveled}}{\text{Time elapsed}}\end{align}`

`\begin{align}&= \frac{4{,}415\text{ km}}{6\text{ hours}} \ &\approx 736.67\text{ km/h}\end{align}`

Rounding to the nearest whole number, we get the average speed of the aeroplane in km/h as $\boxed{737\text{ km/h}}$

`\begin{align}\huge\colorbox{black}{\textcolor{yellow}{I hope this helps !}}\end{align}`

`\begin{align}\colorbox{purple}{\textcolor{lime}{Please mark as brillinest !}}\end{align}`

`\textcolor{cyan}{\small\textit{If you have any further questions, feel free to ask!}}`