Question

Compound A 1. LiAlH4, diethyl ether, 2. H2O --> A

compound B 1, LiAlD4, THF, 2. H2O --> B
compound C 1. LiAlH4, diethyl ether, 2. D3O+ --> C
A acetophenone (a ketone in which the carbonyl carbon is bonded to a benzene ring and a methyl group)
B hexanal (a 6-carbon chain aldehyde where the first carbon is the carbonyl carbon)
C benzaldehyde (an aldehyde in which the carbonyl carbon is bonded to a benzene ring)

Answer 1

Step-by-step explanation:

The given reactions involve reduction of carbonyl compounds using different reducing agents. Specifically, LiAlH4 (lithium aluminum hydride) and LiAlD4 (lithium aluminum deuteride) are strong reducing agents that are capable of reducing ketones and aldehydes to alcohols. D3O+ is a source of deuterium ions (D+) that can replace protons in acidic environments.

In reaction A, acetophenone is reduced to the corresponding alcohol using LiAlH4 in diethyl ether followed by acidic workup with water. This reaction yields 1-phenylethanol as the product.

In reaction B, hexanal is reduced to the corresponding alcohol using LiAlD4 in THF followed by acidic workup with water. This reaction yields 1-hexanol as the product.

In reaction C, benzaldehyde is reduced to the corresponding alcohol using LiAlH4 in diethyl ether followed by acidic workup with D3O+. This reaction yields benzyl alcohol as the product, which contains deuterium atoms incorporated from D3O+.

Overall, these reactions demonstrate the utility of different reducing agents in the reduction of carbonyl compounds, and the incorporation of deuterium atoms using D3O+.