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Find the perimeter of a rectangle whose
length is 9√11 and width is 12√11.

1 Answer

3 votes

The equation for the perimeter of a rectangle is:

2L+2W=P

Knowing this, we can plug in our values to determine P.

L = 9√11

W = 12√11

2(9√11)+2(12√11)=P

(18√11)+(24√11)=P

We can treat the square root of 11 as a variable and add the 18 and 24 giving us:

(42√11)=P

Your "exact" value is 42√11, if you're looking for your approximate value, it's 139.298241195.

Hope this helps.

User Makky
by
7.6k points

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