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What is the standard form of the line that passes through the points (-4,6) and (0,-7)

User Dimpl
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1 Answer

3 votes

Answer:

13x +4y = -28

Explanation:

You want the standard form of the equation for a line through (-4, 6) and (0, -7).

2-point form

One way to write an equation for a line through points (x1, y1) and (x2, y2) is ...

(y2 -y1)(x -x1) -(x2 -x1)(y -y1) = 0

For the given points, this is ...

(-7 -6)(x -(-4)) -(0 -(-4))(y -6) = 0

-13x -52 -4y +24 = 0

Standard form

The standard form of the equation for a line is ...

ax +by = c

where a > 0, and a, b, c are mutually prime.

Adding 13x +4y to the above equation gives ...

13x +4y = -28

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Additional comment

We could get this by simplifying the above equation to ...

-13x -4y -28 = 0

and then multiplying by -1 and subtracting 28. We decided one step was easier, and we didn't have to deal with multiplication by a negative number.

What is the standard form of the line that passes through the points (-4,6) and (0,-7)-example-1
User Alex Heyd
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7.7k points