Question

knowing how many electrons are involved by oxidation difference, how many copper (ii) ions are required per benzoin molecule converting to a benzil molecule? select one: a. 0 b. 3 c. 4 d. 2 e. 1

Answer 1

Two Cu2+ ions are required to oxidize one benzoin molecule to benzil due to the transfer of two electrons per Cu2+ ion, which aligns with answer option D. 2.

Step-by-step explanation:

The conversion of benzoin to benzil involves an oxidation process where two alcohol groups are oxidized to form two carbonyl groups. Each alcohol group loses two electrons during oxidation, requiring a total of four electrons to be removed for one benzoin molecule to convert to benzil. Since each Cu2+ ion accepts one electron during reduction (one electron for each Cu2+ going to Cu1+), we need two Cu2+ ions to accept the two electrons from each alcohol group (four electrons total).

Thus, two Cu2+ ions are required for the complete oxidation of one molecule of benzoin to benzil. The correct answer to the question is therefore D. 2 copper (II) ions per benzoin molecule.

Answer 2

To oxidize benzoin to benzil, two copper (II) ions are required as each can accept one electron and the process requires two electrons in total. The correct answer is d.

Step-by-step explanation:

The question asks how many copper (II) ions are required per benzoin molecule converting to a benzil molecule. The conversion of benzoin to benzil is an oxidation process. In oxidation, benzoin (which has a hydroxyl group) is converted to benzil (which now has a carbonyl group in place of the hydroxyl). This involves the removal of hydrogen atoms and the addition of oxygen to the substrate, which is typically accompanied by the loss of electrons (oxidation).

In the context of copper (II) ions, we need to understand how many electrons each copper ion can accept. As the copper is in the +2 oxidation state, it means it can accept 2 electrons to be reduced to copper (0) state. Knowing that it is a 2-electron process, we can conclude that one molecule of benzoin would require two copper (II) ions to be oxidized to benzil, as each copper (II) ion can accept one electron. Thus, the answer would be d. 2.