Question

PE (J)

A 0.155 kg arrow is shot from
ground level, upward at 31.4 m/s.
What is its potential energy (PE)
when it is 30.0 m above the
ground?

Answer 1

45.6 J

Step-by-step explanation:

PE=mgh

m=0.155 kg

g=9.81 m/s^2

h=30.0 m

0.155(9.81)(30)=45.6