Question

Write the structural formula and name of the organic product for the following reaction between an alkyne and an alkyl halide. (The alkyne group is shown, and should be entered, as "CC", without the triple bond.)

(A.) Product structural formula (formating counts: enter C before associated H atoms; subscript numbers) (e.g., CH3CH2CH2OCHCHCH3)
(B.) Product name:

Answer 1

The product, 2-iodo-1-propyne, can be named systematically as 2-iodo-prop-1-yne. To provide the structural formula and name of the organic product for the reaction between an alkyne and an alkyl halide, assume a generic reaction between a terminal alkyne (CC) and an alkyl halide. The specific alkyl halide and reaction conditions can lead to various products.

Let's consider the reaction between acetylene (CC) and methyl iodide (CH3I). This reaction is an example of an alkylation reaction.

(A.) Product structural formula:

The reaction between acetylene (CC) and methyl iodide (CH3I) can result in the formation of 2-iodo-1-propyne. The structural formula is as follows:

H

|

C ≡ C + CH3I → C ≡ C─C─I

|

H

(B.) Product name:

The product, 2-iodo-1-propyne, can be named systematically as 2-iodo-prop-1-yne.

Answer 2

1. Product's structural formula:
   `CH_3CH_2CH_2C-C-CH_2CH_3`
2. Product's name: 4-Heptyne

The reaction between the alkyne
`CH_3CH_2CH_2CCH` and the alkyl halide
`CH_3CH_2Br` can result in an alkylation product.

The
`NaNH_2` is a strong base that deprotonates the terminal alkyne, creating a nucleophilic acetylide ion. This ion can then undergo a nucleophilic substitution reaction (SN2) with the alkyl halide, resulting in the formation of a new carbon-carbon bond.

The product of this reaction would be
`CH_3CH_2CH_2C-C-CH_2CH_3`.

In other words, the product's structural formula is
`CH_3CH_2CH_2C-C-CH_2CH_3` and the product's name is 4-heptyne.