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A jet aircraft with a mass of 4,550 kg has an engine that exerts a force (thrust) equal to 59,500 N. (a) What is the jet's acceleration when it takes off? (Give the magnitude. )

User Isthmuses
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2 Answers

3 votes

To find the acceleration of the jet aircraft during takeoff, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration:

F_net = m * a

where F_net is the net force, m is the mass, and a is the acceleration.

In this problem, the thrust force of the engine is the net force acting on the aircraft during takeoff. Therefore, we can write:

F_net = 59,500 N

m = 4,550 kg

Substituting these values into the equation above, we get:

59,500 N = 4,550 kg * a

Solving for a, we get:

a = 59,500 N / 4,550 kg

a ≈ 13.08 m/s^2

Therefore, the magnitude of the jet's acceleration during takeoff is 13.08 m/s^2.

User FluxLemur
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8.2k points
4 votes

Answer:

13.23
ms-2

Step-by-step explanation:

59,500 divided by 4,500.

User Ric Santos
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8.6k points