Question

suppose that at the end of its trip, the train slows to a stop from a speed of 22.9 km/h in 6.24 s. what is its average acceleration in m/s2 while stopping? input your answer in m/s2 using 3 significant figures.

Answer 1

-1.02 m/s²

Step-by-step explanation:

The average acceleration of the train while stopping can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. The initial velocity of the train is 22.9 km/h, which is equivalent to 6.36 m/s. The final velocity is 0 m/s since the train comes to a stop. The time taken to stop is 6.24 s. Plugging these values into the formula, we get: acceleration = (0 - 6.36) / 6.24 = -1.02 m/s².

So, the average acceleration of the train while stopping is -1.02 m/s².