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if the molecular weight of nitric acid is 63.01 g/mol and its density is 1.5129 g/ml, what volume (ml) of nitric acid is required?

User Gamliela
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To calculate the required volume of nitric acid, we need to know the mass of the substance required. Let's assume that we need 1 mole of nitric acid. In that case, the mass required would be 63.01 g.

Now, we can use the density of nitric acid to calculate the volume required:

Density of nitric acid = 1.5129 g/mL

Volume of nitric acid = Mass of nitric acid / Density of nitric acid

Volume of nitric acid = 63.01 g / 1.5129 g/mL

Volume of nitric acid = 41.68 mL (rounded to two decimal places)

Therefore, 41.68 mL of nitric acid is required for 1 mole of the substance. If a different amount of nitric acid is required, you can adjust the calculation accordingly.

User Max Tuzenko
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