Question

:

4.) How many moles are in 65.78 g of C6H12O6
(glucose)?
C:
H:
O:
Molar Mass:
=

Answer 1

C: 6

H: 12

O: 6

Molar mass of C6H12O6 = (6 x 12.01 g/mol) + (12 x 1.01 g/mol) + (6 x 16.00 g/mol) = 180.18 g/mol

To find the number of moles in 65.78 g of C6H12O6:

65.78 g / 180.18 g/mol = 0.3656 mol

Therefore, there are approximately 0.366 moles of C6H12O6 in 65.78 g.