Question

Solve these inequalities 1a.4x+12>or equals to 40 1b.3(x+8) 3x+15

Answer 1

1a. 4x + 12 ≥ 40

Subtract 12 from both sides:

4x ≥ 28

Divide both sides by 4:

x ≥ 7

Therefore, the solution is x ≥ 7.

1b. 3(x + 8) ≤ 3x + 15

Distribute the 3:

3x + 24 ≤ 3x + 15

Subtract 3x from both sides:

24 ≤ 15

This inequality is not true for any value of x, so there is no solution.