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How many grams of Na2(SO4) are in 3.5 moles of Na2(SO4)

User Polarblau
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Answer: 497 grams of Na2(SO4) in 3.5 moles of Na2(SO4)

Step-by-step explanation:

The molar mass of Na2(SO4) can be calculated as follows:

2(Na) + 1(S) + 4(O) = 2(23.0 g/mol) + 32.1 g/mol + 4(16.0 g/mol) = 142.0 g/mol

This means that there are 142.0 grams of Na2(SO4) in one mole of the compound.

To find the number of grams in 3.5 moles, we can set up a proportion:

3.5 moles / 1 = x grams / 142.0 g

Solving for x, we get:

x = 3.5 moles x 142.0 g/mole

x = 497 g

Therefore, there are 497 grams of Na2(SO4) in 3.5 moles of Na2(SO4).

User Drrlvn
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