Answer: 497 grams of Na2(SO4) in 3.5 moles of Na2(SO4)
Step-by-step explanation:
The molar mass of Na2(SO4) can be calculated as follows:
2(Na) + 1(S) + 4(O) = 2(23.0 g/mol) + 32.1 g/mol + 4(16.0 g/mol) = 142.0 g/mol
This means that there are 142.0 grams of Na2(SO4) in one mole of the compound.
To find the number of grams in 3.5 moles, we can set up a proportion:
3.5 moles / 1 = x grams / 142.0 g
Solving for x, we get:
x = 3.5 moles x 142.0 g/mole
x = 497 g
Therefore, there are 497 grams of Na2(SO4) in 3.5 moles of Na2(SO4).