Answer:
soo sorry it took me this long to answer.
Step-by-step explanation:
This is a question about acid-base neutralization. According to the search results, when a strong acid (HCl) and a strong base (KOH) are mixed in equal amounts, they react completely to form water and a salt (KCl). The pH of the final solution depends on the amount of excess H+ or OH- ions that remain after the reaction. To find the pH, we need to use the following equations:
pH = -log[H3O+] pOH = -log[OH-] pH + pOH = 14
First, we need to find the number of moles of HCl and KOH in the initial solutions. We can use the formula:
n = MV
where n is the number of moles, M is the molarity, and V is the volume.
For HCl:
n(HCl) = 0.7 M x 0.1 L = 0.07 mol
For KOH:
n(KOH) = 0.5 M x 0.1 L = 0.05 mol
Since HCl and KOH react in a 1:1 ratio, the limiting reactant is KOH. This means that all of the KOH will be consumed in the reaction, and some HCl will be left over. We can find the amount of excess HCl by subtracting the moles of KOH from the moles of HCl:
n(HCl)excess = n(HCl) - n(KOH) = 0.07 mol - 0.05 mol = 0.02 mol
The excess HCl will determine the pH of the final solution, since it will contribute to the concentration of H3O+ ions. To find this concentration, we need to divide the moles of excess HCl by the total volume of the final solution. The total volume is the sum of the initial volumes of HCl and KOH:
Vtotal = V(HCl) + V(KOH) = 0.1 L + 0.1 L = 0.2 L
The concentration of H3O+ ions is then:
[H3O+] = n(HCl)excess / Vtotal = 0.02 mol / 0.2 L = 0.1 M
Finally, we can use the pH equation to find the pH:
pH = -log[H3O+] = -log(0.1) = 1
The pH of the final solution is 1, which means it is acidic.