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HELP 45 PONITS!!

3. f(x) = -0.25x² + 8x - 2
Opens:
Vertex:
Equation for Axis of Symmetry:
Sketch:

HELP 45 PONITS!! 3. f(x) = -0.25x² + 8x - 2 Opens: Vertex: Equation for Axis of Symmetry-example-1

1 Answer

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The given function is a quadratic function in standard form:

f(x) = -0.25x² + 8x - 2

To determine whether the function opens upwards or downwards, we can look at the coefficient of the x² term, which is negative (-0.25). Therefore, the function opens downwards.

The vertex of the function can be found using the formula:

x = -b / (2a)

where a and b are the coefficients of the x² and x terms, respectively. In this case, a = -0.25 and b = 8. Substituting these values into the formula, we get:

x = -8 / (2*(-0.25)) = 16

To find the y-coordinate of the vertex, we can substitute x = 16 into the function:

f(16) = -0.25(16)² + 8(16) - 2 = 62

Therefore, the vertex of the function is (16, 62).

The equation for the axis of symmetry is given by:

x = h

where h is the x-coordinate of the vertex. In this case, h = 16. Therefore, the equation for the axis of symmetry is:

x = 16

To sketch the graph of the function, we can use the vertex and the axis of symmetry to plot the point (16, 62) and draw the axis of symmetry as a vertical line at x = 16. We can also plot a few other points to get an idea of the shape of the graph. For example, we can substitute x = 0 and x = 32 into the function to get:

f(0) = -0.25(0)² + 8(0) - 2 = -2

f(32) = -0.25(32)² + 8(32) - 2 = 30

Plotting these points and connecting them with a smooth curve, we get the following sketch:

Quadratic function sketch


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\begin{align}\colorbox{purple}{\textcolor{lime}{Please mark as brillinest !}}\end{align}


\textcolor{cyan}{\small\textit{If you have any further questions, feel free to ask!}}

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