Question

What are the solutions of the equation 2sin (4x) = 1 on the interval [0,π)? Please show work.

Answer 1

Step-by-step explanation:2sin (4x) = 1 divide both sides by 2. sin (4x) = 1/2. Note that sin (x) = 1/2 at pi/6, 5pi/6, 13pi/6, 17pi/6.