Answer:
-0.4245 J is required.
Step-by-step explanation:
To calculate the work done by the electric field, we can use the formula;
Work done(W) = charge(q) x potential difference(ΔV)
As given in the problem, charge q is a -7.7 mC negative sign due to the charge moving from a lower to a higher potential. The difference in potential is +55v.
Substituting the above-given values in the formula, we get:
Work done(W) = (-7.7 x -10¯³C) x 55V = -0.4245 J
The negative sign in work done indicates work done by the electric field is negative, which means work is done on the charge by the electric field.