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How much work does the electric field do in moving a -7.7 mC from ground to a point whose potential is +55 V higher?

User Thew
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1 Answer

2 votes

Answer:

-0.4245 J is required.

Step-by-step explanation:

To calculate the work done by the electric field, we can use the formula;

Work done(W) = charge(q) x potential difference(ΔV)

As given in the problem, charge q is a -7.7 mC negative sign due to the charge moving from a lower to a higher potential. The difference in potential is +55v.

Substituting the above-given values in the formula, we get:

Work done(W) = (-7.7 x -10¯³C) x 55V = -0.4245 J

The negative sign in work done indicates work done by the electric field is negative, which means work is done on the charge by the electric field.

User Wobmene
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