Question

A single die is rolled twice. the set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}. find the probability of getting two numbers whose sum is greater than 10.

Answer 1

Answer: the probability is 1/9

Step-by-step explanation:

because their is one chance for every nine that you would get a sun larger than 10

Answer 2

To find the probability of getting two numbers whose sum is greater than 10, we need to find the number of outcomes where the sum of the two numbers is greater than 10, and then divide by the total number of outcomes.

There are four possible outcomes where the sum of the two numbers is greater than 10: (4, 6), (5, 6), (6, 5), and (6, 6).

Therefore, the probability of getting two numbers whose sum is greater than 10 is:

number of outcomes where sum is greater than 10 / total number of outcomes

= 4 / 36

= 1 / 9

So the probability of getting two numbers whose sum is greater than 10 is 1/9 or approximately 0.111.