Question

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What is the final volume of a gas at 3.6 atm and 95 mL that has expanded until it has pressure of 0.85 atm?

Answer 1

We can use Boyle's law to solve this problem, which states that the pressure of a gas is inversely proportional to its volume when temperature and amount are held constant. The formula is:

P1V1 = P2V2

Where:

P1 = 3.6 atm (initial pressure)

V1 = 95 mL (initial volume)

P2 = 0.85 atm (final pressure)

V2 = ? (final volume)

Substituting the given values, we get:

(3.6 atm)(95 mL) = (0.85 atm)(V2)

Simplifying, we get:

V2 = (3.6 atm)(95 mL) / (0.85 atm)

V2 = 404.7 mL

Therefore, the final volume of the gas is 404.7 mL.

Answer 2

Answer: 404.71 ML

Step-by-step explanation:

We can use Boyle's Law to solve this problem, which states that the pressure and volume of a gas are inversely proportional at a constant temperature.

Boyle's Law equation: P1V1 = P2V2

Where:

P1 = initial pressure

V1 = initial volume

P2 = final pressure

V2 = final volume

Given:

P1 = 3.6 atm

V1 = 95 mL

P2 = 0.85 atm

We can rearrange the equation to solve for V2:

V2 = (P1V1)/P2

V2 = (3.6 atm * 95 mL)/(0.85 atm)

V2 = 404.71 mL

Therefore, the final volume of the gas is approximately 404.71 mL. Hopefully this helps gang fasho