Question

I know this is a lot but I'm really struggling and if someone can at least answer half, I'll be eternally grateful.

1.
Sodium chlorate decomposes into sodium chloride and oxygen gas as seen in the equation below.

­­2NaClO3­ --> 2NaCl +3O2

How many moles of NaClO3­ were needed to produce 61 moles of O2? Round your answer to the nearest whole number.

2. 3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4 H2O

In the above equation how many moles of NO can be made when 26 moles of HNO3 are consumed?

3. 3 Cu + 8HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O

In the above equation how many moles of water can be made when 75 moles of HNO3 are consumed?

4.
Sodium chlorate decomposes into sodium chloride and oxygen gas as seen in the equation below.

­­2NaClO3­ --> 2NaCl +3O2

How many moles of O2 were produced by 9 moles of NaClO3­? Round your answer to the nearest whole number.

5. For the reaction C + 2H2 → CH4, how many grams of carbon are required to produce 16.1 moles of methane, CH4 ?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element Molar Mass
Hydrogen 1
Carbon 12

6. 3 Cu + 8HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H2O

In the above equation, how many grams of water can be made when 2.1 moles of HNO3 are consumed?



Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element Molar Mass
Hydrogen 1
Nitrogen 14
Copper 63.5
Oxygen 16

7. S + 6 HNO3 → H2SO4 + 6 NO2 + 2 H2O

In the above equation, how many grams of water can be made when 14.1 moles of HNO3 are consumed?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element Molar Mass
Hydrogen 1
Nitrogen 14
Sulfur 32
Oxygen 16

8. 2 NH3 + 3 CuO → 3 Cu + N2 + 3 H2O

In the above equation, how many grams of N2 can be made when 16.7 moles of CuO are consumed?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element Molar Mass
Hydrogen 1
Nitrogen 14
Copper 63.5
Oxygen 16

9. For the reaction C + 2H2 → CH4, how many moles of carbon are needed to make 150.6 grams of methane, CH4 ?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element

Molar Mass

Hydrogen

1

Carbon

12

10. S + 6 HNO3 --> H2SO4 + 6 NO2 + 2 H2O

In the above equation how many moles of water can be made when 113 grams of HNO3 are consumed?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element

Molar Mass

Hydrogen

1

Nitrogen

14

Sulfur

32

Oxygen

16


11. 3 Cu + 8HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O

In the above equation how many moles of water can be made when 117.8 grams of HNO3 are consumed?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element

Molar Mass

Hydrogen

1

Nitrogen

14

Copper

63.5

Oxygen

16


12. 2 NH3 + 3 CuO --> 3 Cu + N2 + 3 H2O

In the above equation how many moles of N2 can be made when 160.9 grams of CuO are consumed?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element

Molar Mass

Hydrogen

1

Nitrogen

14

Copper

63.5

Oxygen

16

Answer 1

To determine the number of moles of NaClO3 required to produce 61 moles of O2, we need to use the stoichiometric coefficients from the balanced equation:

2 NaClO3 → 2 NaCl + 3 O2

For every 2 moles of NaClO3, 3 moles of O2 are produced. Therefore, we can set up a proportion:

2 mol NaClO3 / 3 mol O2 = x mol NaClO3 / 61 mol O2

Solving for x, we get:

x = (2/3) * 61 = 40.67

Rounding to the nearest whole number, we get 41 moles of NaClO3.

From the balanced equation:

3 Cu + 8 HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H2O

We can see that for every 8 moles of HNO3, 2 moles of NO are produced. So for 26 moles of HNO3, we can set up a proportion:

8 mol HNO3 / 2 mol NO = 26 mol HNO3 / x mol NO

Solving for x, we get:

x = (2/8) * 26 = 6.5

Therefore, 6.5 moles of NO can be produced.

From the balanced equation:

3 Cu + 8 HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H2O

We can see that for every 8 moles of HNO3, 4 moles of H2O are produced. So for 75 moles of HNO3, we can set up a proportion:

8 mol HNO3 / 4 mol H2O = 75 mol HNO3 / x mol H2O

Solving for x, we get:

x = (4/8) * 75 = 37.5

Therefore, 37.5 moles of H2O can be produced.

Using the stoichiometric coefficients from the balanced equation:

2 NaClO3 → 2 NaCl + 3 O2

We can see that for every 2 moles of NaClO3, 3 moles of O2 are produced. So for 9 moles of NaClO3, we can set up a proportion:

2 mol NaClO3 / 3 mol O2 = 9 mol NaClO3 / x mol O2

Solving for x, we get:

x = (3/2) * 9 = 13.5

Rounding to the nearest whole number, we get 14 moles of O2.

The balanced equation for the reaction is:

C + 2H2 → CH4

The molar mass of methane (CH4) is 12 (from carbon) + 4(1) (from hydrogen) = 16 g/mol.

To find the mass of carbon required to produce 16.1 moles of CH4, we can use the molar ratio between carbon and methane:

1 mol C / 1 mol CH4

Setting up a proportion:

1 mol C / 1 mol CH4 = x mol C / 16.1 mol CH4

Solving for x, we get:

x = 16.1 mol C

Now we need to convert this to grams using the molar mass of carbon, which is 12 g/mol:

16.1 mol C * 12 g/mol = 193.2 g

Therefore, 193