Question

The net of a square pyramid is shown below: Net of a square pyramid showing 4 triangles and the square base. The square base has side lengths of 2 inches. The height of each triangle attached to the square is 5 inches. The base of the triangle is the side of the square. What is the surface area of the solid? (5 points) a 14 square inches b 20 square inches c 24 square inches d 32 square inches

Answer 1

Explanation:

To find the surface area of the solid square pyramid, we need to find the area of each of the five faces and then add them together.

Since the base of the pyramid is a square with side length of 2 inches, its area is 2^2 = 4 square inches.

Each of the four triangles is a right triangle with height 5 inches and base equal to a side of the square base. Therefore, the area of each triangle is:

(1/2) * base * height = (1/2) * 2 * 5 = 5 square inches

The total area of the four triangles is 4 times the area of one triangle, which is:

4 * 5 = 20 square inches

So, the total surface area of the solid square pyramid is the sum of the area of the base and the area of the four triangles:

4 + 20 = 24 square inches

Therefore, the answer is option (c) 24 square inches.