Answer:
2 and 6
Explanation:
Let's assume, the first digit (ten's place) is x and the second one (unit's place) is y
Let's write 2 equations according to the given information and put them in a system:
{x / y = 3,
{xy = 12;
Let's make x the subject from the 1st equation (it doesn't matter which equation or term (x or y) you choose):
x = 3y
Replace x in the 2nd equation with its new value from the 1st one:
3y * y = 12

Divide both parts by 3 to make x^2 the subject:



x = 3 * 2 = 6