Answer:
3 and 0
Explanation:
Let's assume, the first digit (ten's place) is x and the second one (unit's place) is y
Let's write 2 equations according to the given information and put them in a system (we can write a 2 digit number as 10x + y, and after interchanging: 10y + x
{x - y = 3,
{x - y = 3,{(10x + y) - (10y + x) = 27;
Let's make x the subject from the 1st equation (it doesn't matter which equation or term (x or y) you choose):
x = 3 + y
Replace x in the 2nd equation with its new value from the 1st one:
(10 × (3 + y) + y ) - (10y + (3 + y)) = 27
30 + 10y + y - 10y - 3 - y = 27
Collect like-terms (also, when moving the terms to the other side, make sure to change their sign into the opposite of the previous one):
0y = 0
y = 0
x = 3 + 0 = 3