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2 FeCl3 + 3 Pb(NO3)3 -> 2 Fe(NO3)3 + 3 PbCl₂

How many mol of Fe(NO3)3 will be produced by using 1.5 mol of Pb(NO3)3?

User AkshayT
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2 Answers

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The balanced chemical equation is:

2 FeCl3 + 3 Pb(NO3)2 → 2 Fe(NO3)3 + 3 PbCl2

This equation shows that 2 moles of Fe(NO3)3 are produced for every 3 moles of Pb(NO3)2 consumed.

So, if we start with 1.5 moles of Pb(NO3)3, we can calculate the number of moles of Fe(NO3)3 produced as follows:

(1.5 mol Pb(NO3)3) x (2 mol Fe(NO3)3 / 3 mol Pb(NO3)3) = 1.0 mol Fe(NO3)3

Therefore, 1.0 mole of Fe(NO3)3 will be produced by using 1.5 moles of Pb(NO3)3.
User Frank Kong
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5 votes

Final answer:

For 1.5 moles of Pb(NO3)3, 1 mole of Fe(NO3)3 will be produced.

Step-by-step explanation:

To find the number of moles of Fe(NO3)3 produced, we need to use the stoichiometric ratio between Pb(NO3)3 and Fe(NO3)3. From the balanced equation, we can see that 3 moles of Pb(NO3)3 react to produce 2 moles of Fe(NO3)3. Therefore, for 1.5 moles of Pb(NO3)3, the number of moles of Fe(NO3)3 produced will be:

(1.5 mol Pb(NO3)3) x (2 mol Fe(NO3)3/3 mol Pb(NO3)3) = 1 mol Fe(NO3)3

User Taffy
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