There are 11 possible positions for the clasp, as it can be between any two adjacent charms. If we want the clasp to be between the charms of June and July, we need to count how many of these positions satisfy this condition.
Since there are 12 charms in total, we can arrange them in 12! ways. However, since the order of the charms doesn't matter except for the position of the clasp, we need to divide by 12 to account for the different arrangements of the same set of charms.
Now, we can fix the charms of June and July in their correct positions, which leaves us with 10 remaining charms to arrange. There are 10! ways to do this. However, since we want the clasp to be between the charms of June and July, we need to treat them as a single block and arrange the 10 remaining charms and this block. There are 11 ways to do this.
Therefore, the total number of arrangements where the clasp is between the charms of June and July is 11 × 10!.
The probability of the clasp being between the charms of June and July is:
P = (number of favorable outcomes) / (total number of possible outcomes)
= (11 × 10!) / (12!)
= 11/66
We can represent the possible positions of the clasp using a diagram as follows:
Charm 1 - Charm 2 - Charm 3 - Charm 4 - Charm 5 - Charm 6 - Charm 7 - Charm 8 - Charm 9 - Charm 10 - Charm 11 - Charm 12
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