Question

A 5.00kg box slides down a frictionless plane at an angle of 60.0°. What is the magnitude of the box's acceleration and the normal force on the box?

Answer 1

Step-by-step explanation:

Normal force is mg cos Φ = 5 (9.81) cos (60) = 9.9 N

acceleration

F = ma the downplane force = mg sin Φ

5 * 9.81 sin (60) = 5 (a)

a = 8.5 m/s^2