Answer:
When 5.0 mL of chlorine gas is consumed, 1.3 mL of carbon tetrachloride gas is produced.
Step-by-step explanation:
The balanced chemical equation for the reaction between methane gas and chlorine gas is:
CH4(g) + 4Cl2(g) → 4HCl(g) + CCl4(g)
From this equation, we can see that for every 4 moles of chlorine gas that react, 1 mole of carbon tetrachloride is produced.
To determine the volume of carbon tetrachloride produced when 5.0 mL of chlorine gas is consumed, we need to use the ideal gas law. Assuming standard temperature and pressure (STP), which is 0°C and 1 atm, the volume of one mole of any ideal gas is 22.4 L.
First, we need to calculate the number of moles of chlorine gas consumed:
n(Cl2) = V(Cl2) / Vm(Cl2)
n(Cl2) = 5.0 mL / 22.4 L/mol
n(Cl2) = 0.00022321 mol
According to the balanced equation, 4 moles of chlorine gas react to produce 1 mole of carbon tetrachloride. Therefore, the number of moles of carbon tetrachloride produced is:
n(CCl4) = n(Cl2) / 4
n(CCl4) = 0.00022321 mol / 4
n(CCl4) = 5.58025 x 10^-5 mol
Finally, we can calculate the volume of carbon tetrachloride produced using the ideal gas law:
V(CCl4) = n(CCl4) x Vm(CCl4)
V(CCl4) = 5.58025 x 10^-5 mol x 22.4 L/mol
V(CCl4) = 0.001251 L
Rounding to the correct number of significant digits, the volume of carbon tetrachloride produced is 0.0013 L or 1.3 mL.
Therefore, when 5.0 mL of chlorine gas is consumed, 1.3 mL of carbon tetrachloride gas is produced.