Question

how to calculate and discuss how many cans of 7-UP a 70 kg adult would have to drink to reach a toxic dose. 7-UP is toxic at 12,000 mg/kg and a can is 330mL. Note that the literature value is 0.012 M

Answer 1

First, we need to convert the toxicity value from mg/kg to mg for a 70 kg adult:

Toxic dose for a 70 kg adult = 12,000 mg/kg x 70 kg = 840,000 mg

Next, we need to calculate the number of moles of 7-UP in one can:

Concentration of 7-UP in one can = 0.012 M

Volume of one can = 330 mL = 0.33 L

Number of moles of 7-UP in one can = concentration x volume = 0.012 mol/L x 0.33 L = 0.00396 mol

Finally, we can calculate the number of cans of 7-UP a 70 kg adult would have to drink to reach a toxic dose:

Number of cans of 7-UP = toxic dose / (number of moles in one can x molecular weight of 7-UP)

Molecular weight of 7-UP = 338.14 g/mol

Number of cans of 7-UP = 840,000 mg / (0.00396 mol x 338.14 g/mol) ≈ 619 cans

Therefore, a 70 kg adult would have to drink approximately 619 cans of 7-UP to reach a toxic dose.

Step-by-step explanation: