We can use the formula for the equation of a line to determine any missing values. The formula is:
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y=mx+b
where $m$ is the slope of the line and $b$ is the y-intercept.
We can use the given data points to calculate the slope of the line:
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where $(x_1, y_1)$ and $(x_2, y_2)$ are any two points on the line. Let's use the points $(-9, 3)$ and $(-6, 2)$:
\begin{align*}
m &= \frac{y_2 - y_1}{x_2 - x_1} \
&= \frac{2 - 3}{-6 - (-9)} \
&= \frac{-1}{3}
\end{align*}
Now we can use the slope-intercept form of the equation of a line to determine any missing values. Let's go through each option:
a. Missing $x:-2$, Missing $y:0$
We can use the formula $y = mx + b$ with $m = -\frac{1}{3}$ and $b = 3$ (substitute the coordinates of the point $(-9, 3)$) to find the y-value when $x = -2$:
\begin{align*}
y &= mx + b \
&= -\frac{1}{3} \cdot (-2) + 3 \
&= \frac{7}{3}
\end{align*}
So the missing value of $y$ when $x = -2$ is $\boxed{\frac{7}{3}}$.
b. Missing $x:0$, Missing $y:1$
We can use the formula $y = mx + b$ with $m = -\frac{1}{3}$ and $b = 3$ (substitute the coordinates of the point $(-9, 3)$) to find the y-intercept:
\begin{align*}
y &= mx + b \
3 &= -\frac{1}{3} \cdot (-9) + b \
3 &= 3 + b \
b &= 0
\end{align*}
So the y-intercept is $0$. Now we can substitute $b = 0$ and $m = -\frac{1}{3}$ into the formula $y = mx + b$ to find the y-value when $x = 0$:
\begin{align*}
y &= mx + b \
&= -\frac{1}{3} \cdot 0 + 0 \
&= 0
\end{align*}
So the missing value of $y$ when $x = 0$ is $\boxed{0}$.
c. Missing $x:-2$, Missing $y:2$
We can use the formula $y = mx + b$ with $m = -\frac{1}{3}$ and $b = 3$ (substitute the coordinates of the point $(-9, 3)$) to find the y-value when $x = -2$:
\begin{align*}
y &= mx + b \
&= -\frac{1}{3} \cdot (-2) + 3 \
&= \frac{7}{3}
\end{align*}
So the missing value of $y$ when $x = -2$ is $\boxed{\frac{7