Answer:
Explanation:
Start by substituting the first equation into the second equation to eliminate y:
2x^2 = -3x - 1
Move all terms to one side:
2x^2 + 3x + 1 = 0
Factor the quadratic equation:
(2x + 1)(x + 1) = 0
Solve for x by setting each factor to zero:
2x + 1 = 0 or x + 1 = 0
x = -1/2 or x = -1
Plug in the values of x to find the corresponding values of y:
For x = -1/2:
y = 2(-1/2)^2 = 1/2
For x = -1:
y = 2(-1)^2 = 2
The solutions to the system are (-1/2, 1/2) and (-1, 2).