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Vector u has initial point at (4, 4) and terminal point at (–12, 8). Which are the magnitude and direction of u?

||u|| = 14.422; θ = 33.690°
||u|| = 14.422; θ = 146.310°
||u|| = 16.492; θ = 14.036°
||u|| = 16.492; θ = 165.964°

User Ghostmansd
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1 Answer

0 votes

Let's find the magnitude of each component:

Let:


(x1,y1)=(4,4)


(x2,y2)=(-12,8)


u=ax+by


||u||=√(a^2+b^2)

So, let's find a and b:


a=|x2-x1|=|-12-4|=|-16|=16


b=|y2-y1|=|8-4|=|4|=4

so:


||u||=√(16^2+4^2)


||u||=√(272)


||u||\thickapprox16.492

And the direction is:


\theta=180-\text{tan}^(-1)\huge \text((b)/(a)\huge \text)


\theta=180-\text{tan}^(-1)\huge \text((4)/(16)\huge \text)


\theta\thickapprox180-\text{tan}^(-1)\huge \text((4)/(16)\huge \text)\thickapprox165.964

User Stefan Schmid
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