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On dissolving 28 g of koh in water to form 1 liter of the solution the temperature rises by 6.89°c ,(k=39,h=1,o=16) ,what is the molar heat of the solution of koh ?

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Answer: The heat absorbed by the solution can be calculated using the formula Q = mcT, where Q is the heat absorbed (in Joules), m is the mass of the solution (in kilograms), c is the solution's specific heat capacity (in J/kg K), and T is the temperature change (in K).

We must first determine the solution's mass. We know that 28 grams of KOH were dissolved in one liter of water. Since water has a density of about 1 kg/L, the solution's mass is:

m = 1 kg The next step is to determine the solution's specific heat capacity. It is reasonable to assume that the solution has a specific heat capacity that is comparable to that of water, which is 4.184 J/gK. This must be converted to J/(kg/K), so:

c = 4.184 J/(gK) / 1000 g/kg = 0.004184 J/(kgK) We can now use the equation Q = mcT to determine how much heat the solution absorbs:

The heat absorbed by the solution is 0.029 J, and we can use the definition of molar heat to calculate the molar heat of the KOH solution: Q = (1 kg) (0.004184 J/(kg K)) (6.89 K) = 0.029 J

Molar heat is equal to the heat absorbed divided by the number of moles of KOH. The number of moles of KOH can be determined by dividing the mass of KOH by its molar mass:

n is the ratio of the mass to the molar mass. The molar mass of KOH is equal to 56 g/mol, or (39 + 16 + 1) g/mol. Using this formula, we can determine the molar heat:

The KOH solution has a molar heat of 0.058 J/mol because its molar heat is equal to 0.029 J per 0.5 mol.

Step-by-step explanation:

User Brian Kiernan
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