Question

Calculate the amount of heat required to convert 300 grams at 75 degrees Celsius into steam at 100 degrees Celsius, as the specific heat of water is 4186 J/kg.h and the latent heat of sublimation is 2.66000000

Answer 1

the total amount of heat required to convert 300 grams of water at 75 degrees Celsius into steam at 100 degrees Celsius is 3,940,500 J + 798,000 J = 4,738,500 J.

Step-by-step explanation:

To convert 300 grams of water at 75 degrees Celsius to steam at 100 degrees Celsius, the amount of heat required can be calculated as follows:

First, we need to heat the water from 75 degrees Celsius to 100 degrees Celsius:

Heat required = mass x specific heat x temperature change

Heat required = 300 g x 4186 J/kg°C x (100°C - 75°C)

Heat required = 300 g x 4186 J/kg°C x 25°C

Heat required = 3,940,500 J

Once the water reaches its boiling point at 100 degrees Celsius, we need to supply additional heat to convert the water into steam at the same temperature:

Heat required = mass x latent heat of sublimation

Heat required = 300 g x 2.66000000 J/g

Heat required = 798,000 J