To solve these problems, we can use the distance formula and the concept of symmetry.
A. The distance from point A to the 0yz plane is simply the absolute value of the x-coordinate of point A. Therefore, the distance is:
|2| = 2
So the distance from point A to the 0yz plane is 2 units.
B. The distance from point A to the 0x axis is simply the distance between point A and its projection onto the 0x axis, which is the point (2, 0, 0). Therefore, the distance is:
√[(2-2)^2 + (-4-0)^2 + (-3-0)^2] = √(16 + 9) = √25 = 5
So the distance from point A to the 0x axis is 5 units.
C. To find the coordinates of point A which is symmetric with respect to the 0yz plane, we simply need to negate the x-coordinate of point A. Therefore, the symmetric point is (-2, -4, -3).
D. To find the coordinates of point A which is symmetric about the 0z axis, we simply need to negate the y and x coordinates of point A. Therefore, the symmetric point is (-2, 4, -3).