Question

consider two vector A(18m) Along horizontal and B(8m) at angle of 60° above the horizontal find R and the angle between R and A,A and B

Answer 1

angle between A and B is approximately 76.8°

Step-by-step explanation:

Using the cosine law, we can find the magnitude of the resultant vector R:

R^2 = A^2 + B^2 - 2ABcosθ

where θ is the angle between A and B, which can be found using the sine law:

sinθ/8m = sin60°/18m

θ ≈ 43.2°

Substituting the given values into the cosine law:

R^2 = (18m)^2 + (8m)^2 - 2(18m)(8m)cos(43.2°)

R ≈ 19.4m

The angle between R and A can be found using trigonometry:

tanθ = 8m/18m

θ ≈ 24.4°

Therefore, the angle between R and A is approximately 24.4°, and the angles between A and B and between B and R can be found using the fact that they form a triangle:

180° - 60° - 43.2° = 76.8°

Therefore, the angle between A and B is approximately 76.8°, and the angle between B and R is approximately 60° - 76.8° = -16.8° (because B is above the horizontal).