Question

Standard vinegar solutions are about 5% acetic acid by mass. What is the molarity of a 5% vinegar solution? The molar mass of acetic acid is 60.052 g/mol. The density of the solution is 1.01 g/mL.

Answer 1

Step-by-step explanation:

To calculate the molarity of the vinegar solution, we first need to calculate the number of moles of acetic acid present in one liter of the solution.

Since the density of the solution is 1.01 g/mL, one liter of the solution will have a mass of 1.01 kg.

The mass of acetic acid in one liter of the solution can be calculated as follows:

mass of acetic acid = 5% × 1.01 kg = 0.0505 kg

The number of moles of acetic acid can be calculated using its molar mass:

moles of acetic acid = mass of acetic acid / molar mass of acetic acid

moles of acetic acid = 0.0505 kg / 60.052 g/mol

moles of acetic acid = 0.000841 mol

Therefore, the molarity of the vinegar solution is:

molarity = moles of acetic acid / volume of solution in liters

molarity = 0.000841 mol / 1 L

molarity = 0.000841 M

So, the molarity of a 5% vinegar solution is approximately 0.000841 M.