Question

HELP PLS URGENT

(b) Three forces of magnitude 6 N, 2 N, and 3 N act on a small object in directions North, South, and West respectively. Find the direction and magnitude of the resultant force. If the object is free to move and its mass is 0.2 kg calculate the initial acceleration.​

Answer 1

The net force in the North-South direction is 6 N - 2 N = 4 N towards the North. The net force in the East-West direction is 3 N towards the West. The magnitude of the resultant force can be found using the Pythagorean theorem: sqrt(4^2 + 3^2) = 5 N.

The direction of the resultant force can be found using trigonometry: tan(θ) = 3/4, so θ = arctan(3/4) = 36.87° West of North.

The acceleration of the object can be found using Newton’s second law: F = ma, so a = F/m = (5 N)/(0.2 kg) = 25 m/s^2.

So, the initial acceleration of the object is 25 m/s^2 in the direction

Step-by-step explanation:

36.87° West of North.