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If the equation of the normal to the curve f (X) at the point (2,-1) is X-2 y = 4 , then f (2) =​

User Torger
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To find the value of f(2), we need to use the equation of the normal to the curve at the point (2,-1). We know that the normal to the curve is perpendicular to the tangent at that point.

From the given equation of the normal, we can determine the slope of the tangent line, which is -1/2.

Now we can use the point-slope form of a line to find the equation of the tangent line to the curve at (2,-1): y + 1 = (-1/2)(x - 2).

To solve for f(2), we need to find the y-coordinate of the point on the curve that lies on this tangent line. We can substitute x=2 into the equation of the tangent line to find the y-coordinate: y + 1 = (-1/2)(2 - 2) => y = -1.

Therefore, f(2) = -1.

User Adam Shamsudeen
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