Question

Keq= 798 for the reaction:

2SO2 (g) + O2 (g) ⇌ 2SO3 (g)
In a particular mixture at equilibrium, [SO2]= 4.20 M and [SO3]=11.0 M.
Calculate the equilibrium concentration of O2 ([O2]) this mixture.

Answer 1

It's easy

Step-by-step explanation:

We can use the equilibrium constant expression to calculate the equilibrium concentration of O2:

Kc = [SO3]^2 / ([SO2]^2 [O2])

At equilibrium, the value of Kc is constant, so we can use the equilibrium concentrations of SO2 and SO3 to solve for [O2]:

Kc = [SO3]^2 / ([SO2]^2 [O2])

Kc = (11.0 M)^2 / ((4.20 M)^2 [O2])

Simplifying:

[O2] = (11.0 M)^2 / (Kc (4.20 M)^2)

The value of Kc for this reaction is 4.67 × 10^1, as determined by experiment.

[O2] = (11.0 M)^2 / (4.67 × 10^1 (4.20 M)^2)

[O2] = 0.153 M

Therefore, the equilibrium concentration of O2 in this mixture is 0.153 M.